Oracle SQL限制结果然后显示剩余的结果
发布时间:2021-01-08 02:07:03 所属栏目:站长百科 来源:网络整理
导读:我有一个看起来像这样的表: ID YEAR 1 2001 1 2002 1 20031 20041 20051 20061 20071 20082 1995 2 19962 19972 1998 然后我试过的查询: select "ID",count("Year") "Count",listagg("Year",',') within group (order by "Year") "Years"from ( select dis
我有一个看起来像这样的表: ID YEAR 1 2001 1 2002 1 2003 1 2004 1 2005 1 2006 1 2007 1 2008 2 1995 2 1996 2 1997 2 1998 然后我试过的查询: select "ID",count("Year") "Count",listagg("Year",',') within group (order by "Year") "Years" from ( select distinct tbl2.id "ID",tbl1.year "Year" from table1 tbl1 join table2 tbl2 on(tbl1.tbl2id = tbl2.id) ) group by "ID" 得到了这样的结果: ID Count Years 1 8 2001,2002,2003,2004,2005,2006,2007,2008 2 4 1995,1996,1997,1998 但我想要的是将结果限制为3,但显示剩余的结果如下: ID Count Years 1 3 2001,2003 1 3 2004,2006 1 2 2007,2008 2 3 1995,1997 2 1 1998 解决方法使用ceil函数:select "ID",') within group (order by "Year") "Years" from ( select tbl2.id "ID",tbl1.year "Year",row_number() over ( partition by tbl2.id order by tbl1.year ) rn from table1 tbl1 join table2 tbl2 on(tbl1.tbl2id = tbl2.id) ) group by "ID",ceil(rn/3); SQL Fiddle Demo (编辑:站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |